10y^2+4y-48=0

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Solution for 10y^2+4y-48=0 equation:


Simplifying
10y2 + 4y + -48 = 0

Reorder the terms:
-48 + 4y + 10y2 = 0

Solving
-48 + 4y + 10y2 = 0

Solving for variable 'y'.

Factor out the Greatest Common Factor (GCF), '2'.
2(-24 + 2y + 5y2) = 0

Factor a trinomial.
2((-12 + -5y)(2 + -1y)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(-12 + -5y)' equal to zero and attempt to solve: Simplifying -12 + -5y = 0 Solving -12 + -5y = 0 Move all terms containing y to the left, all other terms to the right. Add '12' to each side of the equation. -12 + 12 + -5y = 0 + 12 Combine like terms: -12 + 12 = 0 0 + -5y = 0 + 12 -5y = 0 + 12 Combine like terms: 0 + 12 = 12 -5y = 12 Divide each side by '-5'. y = -2.4 Simplifying y = -2.4

Subproblem 2

Set the factor '(2 + -1y)' equal to zero and attempt to solve: Simplifying 2 + -1y = 0 Solving 2 + -1y = 0 Move all terms containing y to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1y = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1y = 0 + -2 -1y = 0 + -2 Combine like terms: 0 + -2 = -2 -1y = -2 Divide each side by '-1'. y = 2 Simplifying y = 2

Solution

y = {-2.4, 2}

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